Talk:356: Nerd Sniping

2012-10-24T22:59:35Z

84.197.34.154:

Just because the problem contains an infinite series (or parallel) doesn't mean that it's unsolvable. It's tricky, certainly, and getting the "true" answer involves some rather heavy math, but it's not impossible. Indeed, Google shows that it's already been answered. [[Special:Contributions/76.122.5.96|76.122.5.96]] 20:42, 20 September 2012 (UTC)

I've always had an issue with this problem for one simple reason. In an infinite set of resistors, there is no space to apply a charge, thus there is no resistance. Ohm's law states Resistance = Voltage / I(current). So, in a system where there is no current (creating a divide by zero error), and there is no voltage (no change in electron work capacity, because we don't have a way to excite the electrons, because there is no power) Resistance is incalculable. [[User:Lcarsos|lcarsos]] ([[User talk:Lcarsos|talk]]) 22:22, 20 September 2012 (UTC)

We live in 3 dimensions, just place a battery above the grid with wires going to the 2 points. --[[Special:Contributions/84.197.34.154|84.197.34.154]] 22:59, 24 October 2012 (UTC)

This problem is "unsolvable" only if you try to just use the basic methods for finite networks.
There is a page on this at [http://mathpages.com/home/kmath668/kmath668.htm http://mathpages.com/home/kmath668/kmath668.htm] that reports that the cited points have a resistance of '''4/pi - 1/2''' ohms (.773234... ohms).
The 1/2 ohm resistance between adjacent nodes is actually well known.
[[User:Divad27182|Divad27182]] ([[User talk:Divad27182|talk]]) 05:05, 5 October 2012 (UTC)

explain xkcd - User contributions [en]

Talk:356: Nerd Sniping