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		<title>explain xkcd - User contributions [en]</title>
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		<updated>2026-04-15T21:53:30Z</updated>
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	<entry>
		<id>https://www.explainxkcd.com/wiki/index.php?title=Talk:3015:_D%26D_Combinatorics&amp;diff=357647</id>
		<title>Talk:3015: D&amp;D Combinatorics</title>
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				<updated>2024-11-23T01:35:05Z</updated>
		
		<summary type="html">&lt;p&gt;Kaisheng21: minor elaboration&lt;/p&gt;
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&lt;div&gt;&amp;lt;!--Please sign your posts with ~~~~ and don't delete this text. New comments should be added at the bottom.--&amp;gt;&lt;br /&gt;
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The bot originally created this page as “D Combinatorics”. I renamed it to the correct title and tried to get as many of the references as possible (including a few redirects). [[User:JBYoshi|JBYoshi]] ([[User talk:JBYoshi|talk]]) 00:54, 23 November 2024 (UTC)&lt;br /&gt;
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What are the odds of rolling 16 or higher on 3D6+D4? 3D6 average 10.5, D4 average is 2.5, total average should be 13. I do not know how to proceed from here.&lt;br /&gt;
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:By raw combinatorics: 71 + 52 + 34 + 20 + 10 + 4 + 1 ways to get each of 16 - 22 respectively, for a total of 192, out of 4(6^3) = 864 total. 192/864 simplifies to exactly 2/9. I have no idea how Randall found this; if anyone has an idea, please let me know. [[User:Kaisheng21|Kaisheng21]] ([[User talk:Kaisheng21|talk]]) 01:33, 23 November 2024 (UTC)&lt;br /&gt;
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It seems like we edited the transcript at the same time. The odds of rolling 16 or higher in this situation seem to be 2/9? [[User:Darkmatterisntsquirrels|Darkmatterisntsquirrels]] ([[User talk:Darkmatterisntsquirrels|talk]]) 01:29, 23 November 2024 (UTC)&lt;/div&gt;</summary>
		<author><name>Kaisheng21</name></author>	</entry>

	<entry>
		<id>https://www.explainxkcd.com/wiki/index.php?title=Talk:3015:_D%26D_Combinatorics&amp;diff=357646</id>
		<title>Talk:3015: D&amp;D Combinatorics</title>
		<link rel="alternate" type="text/html" href="https://www.explainxkcd.com/wiki/index.php?title=Talk:3015:_D%26D_Combinatorics&amp;diff=357646"/>
				<updated>2024-11-23T01:33:55Z</updated>
		
		<summary type="html">&lt;p&gt;Kaisheng21: Added explanation of the probability&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&amp;lt;!--Please sign your posts with ~~~~ and don't delete this text. New comments should be added at the bottom.--&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The bot originally created this page as “D Combinatorics”. I renamed it to the correct title and tried to get as many of the references as possible (including a few redirects). [[User:JBYoshi|JBYoshi]] ([[User talk:JBYoshi|talk]]) 00:54, 23 November 2024 (UTC)&lt;br /&gt;
&lt;br /&gt;
What are the odds of rolling 16 or higher on 3D6+D4? 3D6 average 10.5, D4 average is 2.5, total average should be 13. I do not know how to proceed from here.&lt;br /&gt;
&lt;br /&gt;
:By raw combinatorics: 71 + 52 + 34 + 20 + 10 + 4 + 1 ways to get each of 16 - 22 respectively, for a total of 192, out of 4(6^3) = 864 total. 192/864 simplifies to exactly 2/9. I have no idea how Randall found this. [[User:Kaisheng21|Kaisheng21]] ([[User talk:Kaisheng21|talk]]) 01:33, 23 November 2024 (UTC)&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
It seems like we edited the transcript at the same time. The odds of rolling 16 or higher in this situation seem to be 2/9? [[User:Darkmatterisntsquirrels|Darkmatterisntsquirrels]] ([[User talk:Darkmatterisntsquirrels|talk]]) 01:29, 23 November 2024 (UTC)&lt;/div&gt;</summary>
		<author><name>Kaisheng21</name></author>	</entry>

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