Talk:953: 1 to 10 - Revision history

76.176.69.232 at 03:35, 1 February 2026

2026-02-01T03:35:12Z

172.71.166.228 at 17:40, 3 July 2024

2024-07-03T17:40:48Z

172.71.166.228 at 17:40, 3 July 2024

2024-07-03T17:40:19Z

StillNotOriginal: I suck at doing the CAPTCHAs.

2018-05-21T02:16:55Z

I suck at doing the CAPTCHAs.

Condor70 at 13:28, 21 August 2015

2015-08-21T13:28:51Z

108.162.219.217 at 12:32, 26 June 2015

2015-06-26T12:32:49Z

Davidy22: Why did you rearrange the comments on the page?

2015-04-22T14:58:14Z

Why did you rearrange the comments on the page?

173.245.53.238 at 08:16, 22 April 2015

2015-04-22T08:16:49Z

Lackadaisical at 22:03, 26 March 2015

2015-03-26T22:03:30Z

Lackadaisical at 22:01, 26 March 2015

2015-03-26T22:01:06Z

← Older revision		Revision as of 03:35, 1 February 2026
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	Just pronounce numbers as if they were decimal. If you group the digits every 4, use the -yllion and not the -illion system. It's not that hard to say "one, ten, eleven, one hundred, one hundred [and] one, one hundred [and] ten, one hundred [and] eleven, ten hundred, ten hundred [and] one, ten hundred [and] ten, ten hundred [and] eleven, eleven hundred, eleven hundred [and] one, eleven hundred [and] ten, eleven hundred [and] eleven, one myriad" when you count in binary "1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, 1 0000." [[Special:Contributions/172.71.166.228\|172.71.166.228]] 17:40, 3 July 2024 (UTC)		Just pronounce numbers as if they were decimal. If you group the digits every 4, use the -yllion and not the -illion system. It's not that hard to say "one, ten, eleven, one hundred, one hundred [and] one, one hundred [and] ten, one hundred [and] eleven, ten hundred, ten hundred [and] one, ten hundred [and] ten, ten hundred [and] eleven, eleven hundred, eleven hundred [and] one, eleven hundred [and] ten, eleven hundred [and] eleven, one myriad" when you count in binary "1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, 1 0000." [[Special:Contributions/172.71.166.228\|172.71.166.228]] 17:40, 3 July 2024 (UTC)
		+
		+	The question in the comic is actually using ternary, not binary. [[Special:Contributions/76.176.69.232\|76.176.69.232]] 03:35, 1 February 2026 (UTC)

← Older revision		Revision as of 17:40, 3 July 2024
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	I removed the claim that 11 could be interpreted as a (hex) 'B' grade. The grade isn't given as '11', but as '11/100', which would be 'B/64' in hex. [[User:Condor70\|Condor70]] ([[User talk:Condor70\|talk]]) 13:28, 21 August 2015 (UTC)		I removed the claim that 11 could be interpreted as a (hex) 'B' grade. The grade isn't given as '11', but as '11/100', which would be 'B/64' in hex. [[User:Condor70\|Condor70]] ([[User talk:Condor70\|talk]]) 13:28, 21 August 2015 (UTC)

−	Just pronounce numbers as if they were decimal. If you group the digits every 4, use the -yllion and not the -illion system. It's not that hard to say "one, ten, eleven, one hundred, one hundred [and] one, one hundred [and] ten, one hundred [and] eleven, ten hundred, ten hundred [and] one, ten hundred [and] ten, ten hundred [and] eleven, eleven hundred, eleven hundred [and] one, eleven hundred [and] ten, eleven hundred [and] eleven, one myriad" when you count 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, 1 0000.	+	Just pronounce numbers as if they were decimal. If you group the digits every 4, use the -yllion and not the -illion system. It's not that hard to say "one, ten, eleven, one hundred, one hundred [and] one, one hundred [and] ten, one hundred [and] eleven, ten hundred, ten hundred [and] one, ten hundred [and] ten, ten hundred [and] eleven, eleven hundred, eleven hundred [and] one, eleven hundred [and] ten, eleven hundred [and] eleven, one myriad" when you count in binary "1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, 1 0000." [[Special:Contributions/172.71.166.228\|172.71.166.228]] 17:40, 3 July 2024 (UTC)

← Older revision		Revision as of 17:40, 3 July 2024
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	I removed the claim that 11 could be interpreted as a (hex) 'B' grade. The grade isn't given as '11', but as '11/100', which would be 'B/64' in hex. [[User:Condor70\|Condor70]] ([[User talk:Condor70\|talk]]) 13:28, 21 August 2015 (UTC)		I removed the claim that 11 could be interpreted as a (hex) 'B' grade. The grade isn't given as '11', but as '11/100', which would be 'B/64' in hex. [[User:Condor70\|Condor70]] ([[User talk:Condor70\|talk]]) 13:28, 21 August 2015 (UTC)
		+
		+	Just pronounce numbers as if they were decimal. If you group the digits every 4, use the -yllion and not the -illion system. It's not that hard to say "one, ten, eleven, one hundred, one hundred [and] one, one hundred [and] ten, one hundred [and] eleven, ten hundred, ten hundred [and] one, ten hundred [and] ten, ten hundred [and] eleven, eleven hundred, eleven hundred [and] one, eleven hundred [and] ten, eleven hundred [and] eleven, one myriad" when you count 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, 1 0000.

← Older revision		Revision as of 02:16, 21 May 2018
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	"How likely" it is? As everyone knows, "every base is base 10", since every base number in its own numbering system is written as "10" (2 is 10 in binary, 16 is 10 in hex and so on). So that question could be in EVERY number system possible. There are an '''infinite amount of number systems''' that use the symbols 1 and 0. I suppose the probability is then 1 over an infinite number of systems, then very unlikely, so I'd say (as 0 is not in the range of possible answers) the answer is 1. Which, incidentally, is also an acceptable answer for every system. If we want instead to take into account that Megan doesn't know what a 4 is, the possibilities are only base 2, 3 and 4. So the likeliness is 1/3, which corresponds anyway to 1 in those number systems. --[[Special:Contributions/108.162.229.31\|108.162.229.31]] 14:05, 3 June 2014 (UTC)		"How likely" it is? As everyone knows, "every base is base 10", since every base number in its own numbering system is written as "10" (2 is 10 in binary, 16 is 10 in hex and so on). So that question could be in EVERY number system possible. There are an '''infinite amount of number systems''' that use the symbols 1 and 0. I suppose the probability is then 1 over an infinite number of systems, then very unlikely, so I'd say (as 0 is not in the range of possible answers) the answer is 1. Which, incidentally, is also an acceptable answer for every system. If we want instead to take into account that Megan doesn't know what a 4 is, the possibilities are only base 2, 3 and 4. So the likeliness is 1/3, which corresponds anyway to 1 in those number systems. --[[Special:Contributions/108.162.229.31\|108.162.229.31]] 14:05, 3 June 2014 (UTC)
		+
		+	:Naw, there's unary. In unary 1 is \|, 5 is \|\|\|\|\|, ten is \|\|\|\|\|\|\|\|\|\|, and so on. [[User:StillNotOriginal\|S<sup>t<sup>i<sup>l<sup>l</sup></sup></sup></sup><sup>Not</sup>]][[User talk:StillNotOriginal\|<sup><sub>Original</sub></sup>]] 02:16, 21 May 2018 (UTC)
		+

	If we assume '''the question was auditory''' to the questioned, the way '10' was articulated is another source of information: the enquirer can pronounce '10' as ''"ten"'' or ''"one zero"''.		If we assume '''the question was auditory''' to the questioned, the way '10' was articulated is another source of information: the enquirer can pronounce '10' as ''"ten"'' or ''"one zero"''.

← Older revision		Revision as of 13:28, 21 August 2015
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	It seems that the best answer to this question is 1.11111... because it approaches 10 in binary, and is very low in almost any other number system. {{unsigned ip\|173.245.54.169}}		It seems that the best answer to this question is 1.11111... because it approaches 10 in binary, and is very low in almost any other number system. {{unsigned ip\|173.245.54.169}}
		+
		+	I removed the claim that 11 could be interpreted as a (hex) 'B' grade. The grade isn't given as '11', but as '11/100', which would be 'B/64' in hex. [[User:Condor70\|Condor70]] ([[User talk:Condor70\|talk]]) 13:28, 21 August 2015 (UTC)

@@ Line 15: / Line 15: @@
 [[Special:Contributions/93.73.186.104|93.73.186.104]] 16:26, 6 February 2013 (UTC)
 :The absolute value is unnecessary. When is 10 ever less than 1+1?[[Special:Contributions/108.162.219.202|108.162.219.202]] 20:28, 3 January 2014 (UTC)
+::In base -2. [[Special:Contributions/108.162.219.217|108.162.219.217]] 12:32, 26 June 2015 (UTC)
 I don't think the explanation is right, I mean i don't know binary but i don't think the joke is that he's saying a 4 as in 100% [[User:Lackadaisical|Lackadaisical]] ([[User talk:Lackadaisical|talk]]) 00:23, 7 November 2013 (UTC)
 :A 4 is not 100%, but a 3/4 is always 75%. [[Special:Contributions/108.162.212.206|108.162.212.206]] 22:47, 26 January 2014 (UTC)

@@ Line 1: / Line 1: @@
 One of correct answers is P = 1 + 1 - |sgn(10 - 1 - 1)|
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 :A 4 is not 100%, but a 3/4 is always 75%. [[Special:Contributions/108.162.212.206|108.162.212.206]] 22:47, 26 January 2014 (UTC)
 :Actually, my comment was in reference to this: "Since 4 in binary is "100" (one-zero-zero) the joke is that it is 100% likely that the question is binary -- or it could simply be 4 of 10 - which means that the question has evolved into recursive ambiguity. Also, the person asking the question does not know what a 4 is since there is no 4 in binary." The problem I had with it was taken care of in a previous edit (The quote was taken from the 31 December 2013 edit.)--[[User:Lackadaisical|Lackadaisical]] ([[User talk:Lackadaisical|talk]]) 22:03, 26 March 2015 (UTC)
 It seems that the best answer to this question is 1.11111... because it approaches 10 in binary, and is very low in almost any other number system. {{unsigned ip|173.245.54.169}}