Editing 2292: Thermometer
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*Thermodynamically, temperature is the average translational {{w|kinetic energy}} of a group of particles. ''Translational'' kinetic energy means it doesn’t include rotational and vibrational kinetic energy. The relation between a gas’s translational kinetic energy E and its temperature T is | *Thermodynamically, temperature is the average translational {{w|kinetic energy}} of a group of particles. ''Translational'' kinetic energy means it doesn’t include rotational and vibrational kinetic energy. The relation between a gas’s translational kinetic energy E and its temperature T is | ||
::<math>E=\frac32 k_B T,</math> | ::<math>E=\frac32 k_B T,</math> | ||
− | :where k<sub>B</sub> is the {{w|Boltzmann constant}}, 1.380649×10<sup>−23</sup> J⋅K<sup>-1</sup>. So if this thermometer told you a translational kinetic energy measurement in joules, you could get the measured temperature in the Kelvin scale by dividing by the Boltzmann constant and multiplying by 2/3 | + | :where k<sub>B</sub> is the {{w|Boltzmann constant}}, 1.380649×10<sup>−23</sup> J⋅K<sup>-1</sup>. So if this thermometer told you a translational kinetic energy measurement in joules, you could get the measured temperature in the Kelvin scale by dividing by the Boltzmann constant and multiplying by 2/3. |
Using these last three units for home temperature gauging would be ridiculous, as Kelvin and Rankine measurements of body temperature are unfamiliar to the average user and even those familiar with them would need to do calculations to translate normal body temperature. Kinetic energy is obscure enough that only physicists, engineers and thermodynamicists, a relative handful of the potential buyers, would likely know what it refers to. Those that do could make use of the value printed on the thermometer, but such would add a great deal of unnecessary complexity to what should be a simple and intuitive task. | Using these last three units for home temperature gauging would be ridiculous, as Kelvin and Rankine measurements of body temperature are unfamiliar to the average user and even those familiar with them would need to do calculations to translate normal body temperature. Kinetic energy is obscure enough that only physicists, engineers and thermodynamicists, a relative handful of the potential buyers, would likely know what it refers to. Those that do could make use of the value printed on the thermometer, but such would add a great deal of unnecessary complexity to what should be a simple and intuitive task. |