Editing 2379: Probability Comparisons

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| You draw 3 random {{w|M&Ms}} and they're all red
 
| You draw 3 random {{w|M&Ms}} and they're all red
| Depending on the source of one's M&Ms in the U.S., the proportion of reds is either 0.131 or 0.125 .  0.131^3 ≈ 0.225%; 0.125^3 ≈ 0.177% .
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| According to Randall's source, the proportion of reds is 13%.<ref>M&Ms color proportion<br/>13% red<br/>13% brown<br/>14% yellow<br/>16% green<br/>20% orange<br/>24% blue</ref> 0.13<sup>3</sup> ≈ 0.22%.
 
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| 0.3%
 
| 0.3%
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| 20%
 
| 20%
 
| You get a dozen M&Ms and none of them are brown
 
| You get a dozen M&Ms and none of them are brown
| Depending on the source of one's M&Ms in the U.S., the proportion of browns is either 0.124 or 0.125 .  (1 - 0.125)^12 20.1%; (1 - 0.124)^12 20.4% .
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| Depending on the source of one's M&Ms in the U.S., the proportion of browns is either 0.124 or 0.125 .  (1 - 0.125)^12 = 20.1%; (1 - 0.124)^12 = 20.4% .
 
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| 21%
 
| 21%
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| 60%
 
| 60%
 
| You get two M&Ms and neither is blue
 
| You get two M&Ms and neither is blue
| Depending on the source of one's M&Ms in the U.S., the proportion of blues is either 0.207 or 0.25 .  (1 - 0.207)^2 ≈ 62.9%; (1 - 0.25)^2 ≈ 56.3%.
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| The odds that an M&M is not blue is 77%, so the odds that 2 are not blue is (0.77)<sup>2</sup> = 59.29% .
 
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| 65%
 
| 65%
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| 76%
 
| 76%
 
| You get two M&Ms and neither is red
 
| You get two M&Ms and neither is red
| Depending on the source of one's M&Ms in the U.S., the proportion of reds is either 0.131 or 0.125 .  (1 - 0.131)^2 ≈ 75.5%; (1 - .125)^2 ≈ 76.6%.
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| The odds that an M&M is nor red is 85%, so the odds that 2 are not red is 71.9% .
 
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| 77%
 
| 77%
 
| You get an an M&M and it's not blue
 
| You get an an M&M and it's not blue
| Depending on the source of one's M&Ms in the U.S., the proportion of blues is either 0.207 or 0.25 .  (1 - 0.207) = 79.3%; (1 - 0.25) = 75.0%.
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| The odds that an M&M is blue is 23%, so the odds that it's not blue is 77% .
 
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| 78%
 
| 78%

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