Editing Talk:1201: Integration by Parts

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--[[Special:Contributions/128.113.151.84|128.113.151.84]] 04:30, 19 April 2013 (UTC)
 
--[[Special:Contributions/128.113.151.84|128.113.151.84]] 04:30, 19 April 2013 (UTC)
 
: Exactly; he omits the final step part of the process: ∫udv= uv - ∫vdu. This is only helpful if you can easily obtain v from ∫dv and can integrate ∫vdu . The key trick is picking u and dv properly; it's rarely as easy as saying u = f(x) and v=g(x)dx. So the joke is that he's treating integration by parts as if it's a "magic rule" on the order of the product rule for differentiation, when it's not. [[Special:Contributions/66.202.132.250|66.202.132.250]] 21:10, 19 April 2013 (UTC)
 
: Exactly; he omits the final step part of the process: ∫udv= uv - ∫vdu. This is only helpful if you can easily obtain v from ∫dv and can integrate ∫vdu . The key trick is picking u and dv properly; it's rarely as easy as saying u = f(x) and v=g(x)dx. So the joke is that he's treating integration by parts as if it's a "magic rule" on the order of the product rule for differentiation, when it's not. [[Special:Contributions/66.202.132.250|66.202.132.250]] 21:10, 19 April 2013 (UTC)
:: I think this is it. It's funny because the described conversation happens universally every time someone who's not a full-blown math teacher tries to explain IBP to someone else. You just sort of hit this humiliating brick wall if you haven't comprehensively studied it. I'd also like to point out if u = v = x then dv = dx, f(x) = x, g(x) = 1 and your original integral was just ∫x dx to begin with (you wouldn't need IBP in the first place). [[User:Echo Seven|Echo Seven]] ([[User talk:Echo Seven|talk]]) 01:48, 21 April 2013 (UTC)  
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:: I think this is it. It's funny because the described conversation happens universally every time someone who's not a full-blown math teacher tries to explain IBP to someone else. You just sort of hit this humiliating brick wall if you haven't comprehensively studied it. I'd also like to point out if u = v = x then dv = dx, f(x) = x, g(x) = 0 and your original integral was just ∫x dx to begin with (you wouldn't need IBP in the first place). [[User:Echo Seven|Echo Seven]] ([[User talk:Echo Seven|talk]]) 01:48, 21 April 2013 (UTC)  
  
 
Isn't the joke that it's only PART of a guide to integration by parts? Ergo, integration by parts by parts? {{unsigned ip|108.162.238.134}}
 
Isn't the joke that it's only PART of a guide to integration by parts? Ergo, integration by parts by parts? {{unsigned ip|108.162.238.134}}

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