Difference between revisions of "Talk:1208: Footnote Labyrinths"
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The footnote for 6 is actually 1 to the 2 to the 2 [[User:Schmammel|Schmammel]] ([[User talk:Schmammel|talk]]) 12:36, 6 May 2013 (UTC) | The footnote for 6 is actually 1 to the 2 to the 2 [[User:Schmammel|Schmammel]] ([[User talk:Schmammel|talk]]) 12:36, 6 May 2013 (UTC) | ||
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| + | Explaination is wrong : a<sup>b<sup>c</sup></sup> = a<sup>(b<sup>c</sup>)</sup> = a<sup>b^c</sup> (confer the definition of a gogol = 10^100 = 10<sup>10<sup>2</sup></sup>, and a gogolplex = 10^gogol = 10<sup>(10<sup>100</sup>)</sup>, not 10^110. So since 1^2= 1, No<sup>1<sup>2</sup></sup> really means No<sup>1</sup>. | ||
Revision as of 14:55, 6 May 2013
Way to nerd-snipe me, Randall. Alpha (talk) 04:52, 6 May 2013 (UTC)
In the nested-footnotes interpretation, 5 has to be ignored: The 6 must be true, and the 6 says that it’s “actually a 1”, but with footnote 2+2 which says “ibid.” and thus equals footnote 3, which is true. So 6 really does mean actually a 1, which leaves 5 to be ignored. --77.186.8.191 10:47, 6 May 2013 (UTC)
The footnote for 6 is actually 1 to the 2 to the 2 Schmammel (talk) 12:36, 6 May 2013 (UTC)
Explaination is wrong : abc = a(bc) = ab^c (confer the definition of a gogol = 10^100 = 10102, and a gogolplex = 10^gogol = 10(10100), not 10^110. So since 1^2= 1, No12 really means No1.
