Talk:1244: Six Words

I believe the "Oberth Kuiper Manuver" refers not to the exploitation of the Kuiper belt, but to its the maneuver's usefulness for crossing the belt efficiently. There are multiple various points supporting this conclusion:

1. The size and positioning of the circles strongly indicates that they represent Venus, Earth, and Jupiter (or Eve, Kerbin, and Jool). 2. Reaching the Kuiper belt (which begins at Neptune) requires a great deal of delta-v. Even if you were to slingshot around gas giants (which, in the current explanation, is not shown in the diagram), the trip would consume the majority of a spacecraft's propellant, making the extreme exploitation of the Oberth effect largely ineffective. 3. Kuiper belt objects are very small and therefore would not effectively serve to redirect or slingshot the spacecraft.

66.159.155.170 10:11, 29 July 2013 (UTC)

"This makes no sense, as it it is vastly more expensive in terms of fuel to get to a Kuiper belt object (which is at least 10 billion km from earth) than it is to get to the sun."

This is incorrect. To go directly to the Sun takes a delta-v about equal to Earth's orbital speed (30 km/s). Escape speed is √2 * v_c = 42 km/s; since you start with v_c, you need a delta-v of 12 km/s to get out to the Kuiper Belt. Once you're far from the Sun, a very small delta-v will put you on an orbit passing near (or into) the Sun. Wwoods (talk) 16:47, 29 July 2013 (UTC)

Okay, that's true. But I have another objection to the interpretation: how long would it take to get a probe to the Kuiper belt? And of course there's the problem of actually finding a Kuiper belt object to slingshot around, especially when you've got much better candidates, e.g. Jupiter, Saturn, etc. available for the maneuver…

strictly an orbiter shop

According to this [1] that is not true. 212.90.151.90 11:59, 29 July 2013 (UTC)

Indeed - thanks! I added that in. Now, is there any evidence that they play Orbiter?? Nealmcb (talk) 16:55, 29 July 2013 (UTC)