Talk:1935: 2018

This is easy! Don't factor it - just multiply by 25 and if that ends in two zeros, but not four zeros then it's a leap year, at least most of the time.....17:25, 29 December 2017 (UTC) 162.158.126.112 (talk) (please sign your comments with ~~~~)

This is easy! Don’t factor it - just convert it into a binary and look at the 2 least significant bits. If they are 00 the number is multiple of four. —172.69.33.35 17:37, 29 December 2017 (UTC)

This is easy! Don't factor it - just subtract 4 repeatedly. If you end up at 0, it's divisible. If you end up at 1, 2, or 3, it's not. -- 17:55, 29 December 2017 (UTC) 172.68.58.167 (talk) (please sign your comments with ~~~~)

The calculation of Christmas is trivial^{[citation needed]} it's December 25th. Where as the calculation of Easter is complex ([1]). 172.68.133.18 18:03, 29 December 2017 (UTC)

Title text explanation mis-read

Explanation of title text is incorrect: "The title text refers to calculating the date of Christmas; again, this is a trivial exercise, because Christmas is always December 25." Title text states 'day of Christmas', not 'date...'. The day changes each year and so does require calculation. 162.158.111.73 (talk) (please sign your comments with ~~~~)

Oops, my bad. Fixed. FlyingPiMonster (talk) 18:08, 29 December 2017 (UTC)

• I think you have it backwards. The title text is a reference to calculating the day (as in "date", not "day of week") of Easter. This is a non-trivial calculation (though one that modern computers can perform easily). On the other hand, the Christmas day is fixed. (There's no reason to believe that the joke was anything else.) - Mike Rosoft (talk) 19:13, 29 December 2017 (UTC)

I don't know who wrote the explanation, but... Are they having a bad day? 162.158.111.205 18:44, 29 December 2017 (UTC)

That was vandalism. I did a revert. --Dgbrt (talk) 19:06, 29 December 2017 (UTC)

Also, Megan understands that checking if a number divisible by 2 is easy 141.101.77.50 19:32, 29 December 2017 (UTC)