# Talk:953: 1 to 10

1.(1) is the best answer I've got Halfhat (talk) 11:53, 5 April 2014 (UTC)

"How likely" it is? As everyone knows, "every base is base 10", since every base number in its own numbering system is written as "10" (2 is 10 in binary, 16 is 10 in hex and so on). So that question could be in EVERY number system possible. There are an **infinite amount of number systems** that use the symbols 1 and 0. I suppose the probability is then 1 over an infinite number of systems, then very unlikely, so I'd say (as 0 is not in the range of possible answers) the answer is 1. Which, incidentally, is also an acceptable answer for every system. If we want instead to take into account that Megan doesn't know what a 4 is, the possibilities are only base 2, 3 and 4. So the likeliness is 1/3, which corresponds anyway to 1 in those number systems. --108.162.229.31 14:05, 3 June 2014 (UTC)

If we assume **the question was auditory** to the questioned, the way '10' was articulated is another source of information: the enquirer can pronounce '10' as *"ten"* or *"one zero"*.
In the first case, if he said *"ten"*, this points towards the base system being greater than/equal to 10. For example *"ten"* would be "10" in decimal (base 10) and "16" in hexadecimal (base 16). The word "ten" stops making sense for bases 2 through 9, which leads us to the conclusion of this case: the probability of the question being base 2 is zero, therefore the closest possible score one can give is 1.
In the case that "10" is pronounced *"one zero"*: using the same logic as in the first case, the question can use any base 2 through 9. giving us a probability of 1/8, the nearest score again being 1.

So if the question were: "On a scale from one to one zero, how likely is this question using the decimal system?" Could be answered with full confidence

One of correct answers is P = 1 + 1 - |sgn(10 - 1 - 1)|

(|x| is absolute value of x, sgn(x) is 1 when x > 0, 0 when x = 0, and -1 when x < 0)

If 10 = 1 + 1, then P = 10 - |sgn(0)| = 10 - |0| = 10

If 10 > 1 + 1, then P = 1 + 1 - |sgn(10 - 1 - 1)| = 1 + 1 - |1| = 1

If 10 < 1 + 1, then P = 1 + 1 - |sgn(10 - 1 - 1)| = 1 + 1 - |-1| = 1

So P is 10 iif the question was is in binary, and 1 iif it was not in binary.

93.73.186.104 16:26, 6 February 2013 (UTC)

- The absolute value is unnecessary. When is 10 ever less than 1+1?108.162.219.202 20:28, 3 January 2014 (UTC)

I don't think the explanation is right, I mean i don't know binary but i don't think the joke is that he's saying a 4 as in 100% Lackadaisical (talk) 00:23, 7 November 2013 (UTC)

- A 4 is not 100%, but a 3/4 is always 75%. 108.162.212.206 22:47, 26 January 2014 (UTC)
- Actually, my comment was in reference to this: "Since 4 in binary is "100" (one-zero-zero) the joke is that it is 100% likely that the question is binary -- or it could simply be 4 of 10 - which means that the question has evolved into recursive ambiguity. Also, the person asking the question does not know what a 4 is since there is no 4 in binary." The problem I had with it was taken care of in a previous edit (The quote was taken from the 31 December 2013 edit.)--Lackadaisical (talk) 22:03, 26 March 2015 (UTC)

It seems that the best answer to this question is 1.11111... because it approaches 10 in binary, and is very low in almost any other number system. 173.245.54.169 (talk) *(please sign your comments with ~~~~)*