Editing Talk:2073: Kilogram
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− | + | US weight and length units definition is strictly based on metric system: | |
+ | "Standards for the exact length of an inch have varied in the past, but since the adoption of the international yard during the 1950s and 1960s it has been based on the metric system and defined as exactly 2.54 cm."{https://en.wikipedia.org/wiki/Inch} | ||
+ | "the most common today is the international avoirdupois pound, which is legally defined as exactly 0.45359237 kilograms" {https://en.wikipedia.org/wiki/Pound_(mass)} | ||
+ | Therefore the conversion proposed sounds recursive. | ||
+ | Also, https://www.youtube.com/watch?v=SmSJXC6_qQ8 | ||
+ | [[Special:Contributions/172.68.51.178|172.68.51.178]] 13:49, 17 November 2018 (UTC) | ||
I didn't know that weights and currencies could be converted 1:1, that's cool! [[User:Fabian42|Fabian42]] ([[User talk:Fabian42|talk]]) 16:37, 16 November 2018 (UTC) | I didn't know that weights and currencies could be converted 1:1, that's cool! [[User:Fabian42|Fabian42]] ([[User talk:Fabian42|talk]]) 16:37, 16 November 2018 (UTC) | ||
I wish they ''had'' redefined the kilogram a little bit. It would have been neat if 1 kg was exactly the weight of 1 dm^3 (1 litre) of water under one atmosphere of pressure. Right now it's soooo close. It's a good enough estimate for simple maths, but whenever you tell people that a litre of water weighs one kilogram the pedants comes out of the woodworks... [[User:Kapten-N|Kapten-N]] ([[User talk:Kapten-N|talk]]) 16:50, 16 November 2018 (UTC) | I wish they ''had'' redefined the kilogram a little bit. It would have been neat if 1 kg was exactly the weight of 1 dm^3 (1 litre) of water under one atmosphere of pressure. Right now it's soooo close. It's a good enough estimate for simple maths, but whenever you tell people that a litre of water weighs one kilogram the pedants comes out of the woodworks... [[User:Kapten-N|Kapten-N]] ([[User talk:Kapten-N|talk]]) 16:50, 16 November 2018 (UTC) | ||
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:You'll get pedants whenever you refer to a kilogram as weight; it's a mass. The difference is that stuff weighs less on the Moon - or on tall mountains - although the mass is the same. I think the article as I just read it gets away with this. And, sure, what is the standard kilogram but a weight, that you take and weigh... [email protected] [[Special:Contributions/162.158.91.59|162.158.91.59]] 23:57, 16 November 2018 (UTC) | :You'll get pedants whenever you refer to a kilogram as weight; it's a mass. The difference is that stuff weighs less on the Moon - or on tall mountains - although the mass is the same. I think the article as I just read it gets away with this. And, sure, what is the standard kilogram but a weight, that you take and weigh... [email protected] [[Special:Contributions/162.158.91.59|162.158.91.59]] 23:57, 16 November 2018 (UTC) | ||
::It ''used'' to be a mass. Now it's a ratio of the local gravitational strength versus the efficiency of an EM field. Kibble scales require EM shielding & an environment of ''precisely'' 1g, in order to be accurate. Since gravity isn't equal everywhere, our measurements of kilograms will now vary accordingly. [[User:ProphetZarquon|ProphetZarquon]] ([[User talk:ProphetZarquon|talk]]) 08:36, 17 November 2018 (UTC) | ::It ''used'' to be a mass. Now it's a ratio of the local gravitational strength versus the efficiency of an EM field. Kibble scales require EM shielding & an environment of ''precisely'' 1g, in order to be accurate. Since gravity isn't equal everywhere, our measurements of kilograms will now vary accordingly. [[User:ProphetZarquon|ProphetZarquon]] ([[User talk:ProphetZarquon|talk]]) 08:36, 17 November 2018 (UTC) | ||
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Up until 1964 a litre (and therefore actually the metre too) used to be defined as the volume that water with mass 1kg takes. But this is not good for exact measurements not only because you need exactly reproducable temperature, pressure (not so problematic, because you can measure them and then calculate the divergence) and gravity (not so easy to measure, because you need an exact mass and exact masses are impossible to keep the same), but also because you need pure water free of any polutions of other stuff (hard and expensive) and even free of tiny amounts of isotopes which are deuterium and tritium (even way more expensive). | Up until 1964 a litre (and therefore actually the metre too) used to be defined as the volume that water with mass 1kg takes. But this is not good for exact measurements not only because you need exactly reproducable temperature, pressure (not so problematic, because you can measure them and then calculate the divergence) and gravity (not so easy to measure, because you need an exact mass and exact masses are impossible to keep the same), but also because you need pure water free of any polutions of other stuff (hard and expensive) and even free of tiny amounts of isotopes which are deuterium and tritium (even way more expensive). | ||
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:But how do you define/measure a Joule then? [[User:Fabian42|Fabian42]] ([[User talk:Fabian42|talk]]) 18:19, 16 November 2018 (UTC) | :But how do you define/measure a Joule then? [[User:Fabian42|Fabian42]] ([[User talk:Fabian42|talk]]) 18:19, 16 November 2018 (UTC) | ||
:No, until 1964, meter and litre were totally independent, a meter has never been defined directly or indirectly in relation to a mass of water. It is only since 1964 that the liter is defined as a cubic decimeter.[[Special:Contributions/162.158.90.36|162.158.90.36]] 18:36, 16 November 2018 (UTC) | :No, until 1964, meter and litre were totally independent, a meter has never been defined directly or indirectly in relation to a mass of water. It is only since 1964 that the liter is defined as a cubic decimeter.[[Special:Contributions/162.158.90.36|162.158.90.36]] 18:36, 16 November 2018 (UTC) | ||
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:Also, in E=mc², E is the energy '''at rest''' (for a stationary object of mass m), so your definition using the acceleration makes no sense.[[Special:Contributions/162.158.88.254|162.158.88.254]] 18:47, 16 November 2018 (UTC) | :Also, in E=mc², E is the energy '''at rest''' (for a stationary object of mass m), so your definition using the acceleration makes no sense.[[Special:Contributions/162.158.88.254|162.158.88.254]] 18:47, 16 November 2018 (UTC) | ||
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Actually, for the new definition of the kilo using the Kibble balance you need to measure the gravity... [[Special:Contributions/162.158.134.16|162.158.134.16]] 17:34, 16 November 2018 (UTC) | Actually, for the new definition of the kilo using the Kibble balance you need to measure the gravity... [[Special:Contributions/162.158.134.16|162.158.134.16]] 17:34, 16 November 2018 (UTC) | ||
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:::The idea is that with twelve parts, you can have 1/2, 1/3, 1/4, 1/6, and 1/12 all be integer number of parts. This is why these types of systems developed in the past, and why so many systems also had multiples of 60 (you can do the math here.). They were easy to divide by merchants without access to any sort of calculation method. The base-10 system is great if you're only ever dealing with halves or tenths. But if you want a quarter or a third of something, you have to split the base units. It's no longer necessary in modern life, but it had a real advantage in ancient times. [[User:Cgrimes85|Cgrimes85]] ([[User talk:Cgrimes85|talk]]) 19:18, 16 November 2018 (UTC) | :::The idea is that with twelve parts, you can have 1/2, 1/3, 1/4, 1/6, and 1/12 all be integer number of parts. This is why these types of systems developed in the past, and why so many systems also had multiples of 60 (you can do the math here.). They were easy to divide by merchants without access to any sort of calculation method. The base-10 system is great if you're only ever dealing with halves or tenths. But if you want a quarter or a third of something, you have to split the base units. It's no longer necessary in modern life, but it had a real advantage in ancient times. [[User:Cgrimes85|Cgrimes85]] ([[User talk:Cgrimes85|talk]]) 19:18, 16 November 2018 (UTC) | ||
:::: No longer necessary in modern life... Which is why we should all switch to base-10 units of time! [[User:ProphetZarquon|ProphetZarquon]] ([[User talk:ProphetZarquon|talk]]) 08:36, 17 November 2018 (UTC) | :::: No longer necessary in modern life... Which is why we should all switch to base-10 units of time! [[User:ProphetZarquon|ProphetZarquon]] ([[User talk:ProphetZarquon|talk]]) 08:36, 17 November 2018 (UTC) | ||
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Ok, I'm going to point out something. What's a meter? 1000 milimeters. What's a milimeter? .....skipping the questions all the way to the end, the answer is "the wavelength of the color orange". Or at least that's what I read. So my question is: why orange? What's so special about orange? What as a species or as a solar system or as universe does the color orange have to do with anything? [[Special:Contributions/172.68.90.10|172.68.90.10]] 21:50, 16 November 2018 (UTC) SiliconWolf | Ok, I'm going to point out something. What's a meter? 1000 milimeters. What's a milimeter? .....skipping the questions all the way to the end, the answer is "the wavelength of the color orange". Or at least that's what I read. So my question is: why orange? What's so special about orange? What as a species or as a solar system or as universe does the color orange have to do with anything? [[Special:Contributions/172.68.90.10|172.68.90.10]] 21:50, 16 November 2018 (UTC) SiliconWolf | ||
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: "The metre was originally defined in 1793 as one ten-millionth of the distance from the equator to the North Pole." That's why orange. Think of those lines from equator to pole... and how an orange is divided in segments beneath the peel. This is why the "Terry's Chocolate Orange" is so called, because it resembles the fruit orange. [email protected] [[Special:Contributions/162.158.91.59|162.158.91.59]] 23:51, 16 November 2018 (UTC) | : "The metre was originally defined in 1793 as one ten-millionth of the distance from the equator to the North Pole." That's why orange. Think of those lines from equator to pole... and how an orange is divided in segments beneath the peel. This is why the "Terry's Chocolate Orange" is so called, because it resembles the fruit orange. [email protected] [[Special:Contributions/162.158.91.59|162.158.91.59]] 23:51, 16 November 2018 (UTC) | ||
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:I feel like we're starting to compare angstroms & millitrumps, here. [[User:ProphetZarquon|ProphetZarquon]] ([[User talk:ProphetZarquon|talk]]) 08:36, 17 November 2018 (UTC) | :I feel like we're starting to compare angstroms & millitrumps, here. [[User:ProphetZarquon|ProphetZarquon]] ([[User talk:ProphetZarquon|talk]]) 08:36, 17 November 2018 (UTC) | ||
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'''Be very careful''' | '''Be very careful''' | ||
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It will be very funny when we find out one of those constants is not really constant ... sure, planck length is less likely to change than physical object, but it MIGHT. Like, maybe it gets longer the older the universe is ... -- [[User:Hkmaly|Hkmaly]] ([[User talk:Hkmaly|talk]]) 23:17, 16 November 2018 (UTC) | It will be very funny when we find out one of those constants is not really constant ... sure, planck length is less likely to change than physical object, but it MIGHT. Like, maybe it gets longer the older the universe is ... -- [[User:Hkmaly|Hkmaly]] ([[User talk:Hkmaly|talk]]) 23:17, 16 November 2018 (UTC) | ||
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:Since they're proposing to measure the gravitational force exerted on a unit of mass against the force exerted by an electromagnetic field (instead of comparing the downward force exerted on two masses), the new definition ''isn't'' a constant. For instance, on the moon such a scale would define 1kg as about 13.3lbs! The "new official definition" is a bad one. [[User:ProphetZarquon|ProphetZarquon]] ([[User talk:ProphetZarquon|talk]]) 08:36, 17 November 2018 (UTC) | :Since they're proposing to measure the gravitational force exerted on a unit of mass against the force exerted by an electromagnetic field (instead of comparing the downward force exerted on two masses), the new definition ''isn't'' a constant. For instance, on the moon such a scale would define 1kg as about 13.3lbs! The "new official definition" is a bad one. [[User:ProphetZarquon|ProphetZarquon]] ([[User talk:ProphetZarquon|talk]]) 08:36, 17 November 2018 (UTC) | ||
You could not define the kilogram in terms of electric force when you defined the Amp in terms of the current that creates a given force. But by defining the amp in terms of numbers of elementary charges per second and setting Avogadro and other constants by fiat, you break the circle. [[Special:Contributions/162.158.38.190|162.158.38.190]] 23:54, 16 November 2018 (UTC) | You could not define the kilogram in terms of electric force when you defined the Amp in terms of the current that creates a given force. But by defining the amp in terms of numbers of elementary charges per second and setting Avogadro and other constants by fiat, you break the circle. [[Special:Contributions/162.158.38.190|162.158.38.190]] 23:54, 16 November 2018 (UTC) | ||
− | In the Netherlands, we use the metric system. We also use the term "pond" to mean pound. However, we use metric pounds. Those are 0.500 kilogram, so it is actually easy to use. | + | In the Netherlands, we use the metric system. We also use the term "pond" to mean pound. However, we use metric pounds. Those are 0.500 kilogram, so it is actually easy to use. |
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While it would be nice if the meter were equal to a yard, it would certainly be better if the meter were defined as 5.28 feet, so that kilometers and miles are the same.[[User:Mathmannix|Mathmannix]] ([[User talk:Mathmannix|talk]]) 13:54, 17 November 2018 (UTC) | While it would be nice if the meter were equal to a yard, it would certainly be better if the meter were defined as 5.28 feet, so that kilometers and miles are the same.[[User:Mathmannix|Mathmannix]] ([[User talk:Mathmannix|talk]]) 13:54, 17 November 2018 (UTC) | ||
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