Editing Talk:216: Romantic Drama Equation
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:He says for large casts. For 2000 cast members, with 1000 of each gender, the gay couplings comes out at 999,000 and straight at 1,000,000. Presumably this is the small cross over the diagram alludes to. If you substitute x = n/2 into the equations, then you get (n^2-2n)/4 for the gay combinations and n^2/4 for the straight combinations, so for gender balanced cast size of n, the straight combinations outnumber the gay by n/2 {{unsigned ip | 141.101.98.229}} | :He says for large casts. For 2000 cast members, with 1000 of each gender, the gay couplings comes out at 999,000 and straight at 1,000,000. Presumably this is the small cross over the diagram alludes to. If you substitute x = n/2 into the equations, then you get (n^2-2n)/4 for the gay combinations and n^2/4 for the straight combinations, so for gender balanced cast size of n, the straight combinations outnumber the gay by n/2 {{unsigned ip | 141.101.98.229}} | ||
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There is a typo in his formula for gay casts. The + should be a -. {{unsigned ip|199.27.128.159}} | There is a typo in his formula for gay casts. The + should be a -. {{unsigned ip|199.27.128.159}} |