Editing 1935: 2018
Warning: You are not logged in. Your IP address will be publicly visible if you make any edits. If you log in or create an account, your edits will be attributed to your username, along with other benefits.
The edit can be undone.
Please check the comparison below to verify that this is what you want to do, and then save the changes below to finish undoing the edit.
Latest revision | Your text | ||
Line 1: | Line 1: | ||
− | |||
{{comic | {{comic | ||
| number = 1935 | | number = 1935 | ||
Line 9: | Line 8: | ||
==Explanation== | ==Explanation== | ||
− | + | {{incomplete|Anything missing? - Please change this comment when editing this page. Do NOT delete this tag too soon.}} | |
− | + | In this [[:Category:New Year|New Year comic]], [[Megan]] wonders if 2018 will be a leap year. [[Cueball]] thinks 2018 will not be a leap year, and Megan responds that she "doubts anyone knows at this point." This appears to be a jab at the complexity of the leap year system. As Cueball says, leap years occur every four years (though there are a few exceptions), adding an extra day to account for the fact that Earth takes a bit longer than 365 days to orbit the Sun. Therefore, most years that are a multiple of four are leap years. As Megan says, this is easy for odd-numbered years, since no odd numbers are divisible by four. However, for even-numbered years, it isn't always obvious. | |
− | + | The last panel expresses a misunderstanding of modern {{w|Cryptography|cryptography}}, which relies on the fact that it is difficult to factorize large numbers. Megan is applying this concept to the year, claiming that it is hard to determine whether or not 2018 is a multiple of four and hence is a leap year. In reality, factorization is not needed here, since we already know the factor, which is four. Megan states that if it were possible to factor large numbers with a calculator, modern cryptography would collapse. While true, it is only true for truly large numbers (hundreds of digits), and no factorization is needed in this case. | |
− | + | At the end of the strip, Megan hopes the answer can be {{w|Brute-force attack|brute-forced}} by February. Brute force is a method of breaking cryptography by trying every possible option until one works. This is a misdirection upon misdirection, in that even if we needed to factorize 2018 (which we don't), the simplest brute forcing algorithm would only need to try 43 numbers - from 2 to square root of 2018 (44). In cryptography, the algorithms use numbers much, much bigger than 2018 -- on the order of hundreds (or even thousands) of digits. | |
− | + | The title text refers to calculating which day of the week Christmas will fall on. Given that any calendar will easily tell you, this is not a difficult thing to calculate. Also it always falls on December 25th, and not like, for instance, Easter which date jumps from year to year. But nevertheless December 25th is either the 359th or the 360th (leap years) day of the year and so the day of the week could be different. | |
+ | |||
+ | Wikipedia and many other sites reveal spoilers for this comic: | ||
+ | <blockquote>Every year that is exactly divisible by four is a leap year, except for years that are exactly divisible by 100, but these centurial years are leap years if they are exactly divisible by 400. For example, the years 1700, 1800, and 1900 were not leap years, but the years 1600 and 2000 were.<ref>[http://aa.usno.navy.mil/faq/docs/calendars.php Introduction to Calendars]. (15 May 2013). [[United States Naval Observatory]].</ref></blockquote> | ||
+ | |||
+ | 2018 is not divisible by 4, so the year is not a leap year. 2016 and 2020 are leap years. Assuming your calendar is Gregorian! (Actually, also the case if it is 2018 on the old Julian calendar. The century year rules for leap years are different on the Gregorian calendar from the Julian, but the non-century year rules are the same). | ||
+ | |||
+ | A year is roughly 365.2422 days long. | ||
==Transcript== | ==Transcript== | ||
Line 41: | Line 47: | ||
==Trivia== | ==Trivia== | ||
− | *Released on Friday, December 29, this | + | *Released on Friday, December 29, this is the last comic of 2017. The next scheduled comic will be on New Year's Day of 2018. |
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | *This is the third year in a row with New Year's comics with only the year used as the title | + | *This is the third year in a row with New Year's comics with only the year used as the title, before that there were two more comics with such titles, but those two (and thus the first three) were only released in the even years: [[998: 2012]] in 2012, [[1311: 2014]] in 2014, [[1624: 2016]] in 2016 and [[1779: 2017]] in 2017. |
{{comic discussion}} | {{comic discussion}} | ||
Line 59: | Line 57: | ||
[[Category:Comics featuring Cueball]] | [[Category:Comics featuring Cueball]] | ||
[[Category:Comics sharing name|2017]] | [[Category:Comics sharing name|2017]] | ||
− | [[Category: | + | [[Category:Math]] |
− | [[Category: | + | [[Category:Time]] |
[[Category:Cryptography]] | [[Category:Cryptography]] |