Difference between revisions of "Talk:2750: Flatten the Planets"
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: The discs are centered on the orbit of the parent planet, and presumably rotating at the same frequency as the parent planet's orbit. That means the inner edge of each disc is going slower than you'd need to orbit the Sun at that distance, and the outer edge faster. If you moved inward from the original planet's orbit, the Sun's gravity would pull you in, but when you crossed the boundary to the next disc, you'd get flung back outward.[[Special:Contributions/162.158.62.61|162.158.62.61]] 19:58, 15 March 2023 (UTC) | : The discs are centered on the orbit of the parent planet, and presumably rotating at the same frequency as the parent planet's orbit. That means the inner edge of each disc is going slower than you'd need to orbit the Sun at that distance, and the outer edge faster. If you moved inward from the original planet's orbit, the Sun's gravity would pull you in, but when you crossed the boundary to the next disc, you'd get flung back outward.[[Special:Contributions/162.158.62.61|162.158.62.61]] 19:58, 15 March 2023 (UTC) | ||
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| + | This makes about as much sense as other Flat Earth theories. [[Special:Contributions/172.70.200.137|172.70.200.137]] 20:00, 15 March 2023 (UTC) | ||
Revision as of 20:00, 15 March 2023
I have to wonder, would you slide down to the sun, or be flung outwards? SDSpivey (talk) 19:39, 15 March 2023 (UTC)
- The discs are centered on the orbit of the parent planet, and presumably rotating at the same frequency as the parent planet's orbit. That means the inner edge of each disc is going slower than you'd need to orbit the Sun at that distance, and the outer edge faster. If you moved inward from the original planet's orbit, the Sun's gravity would pull you in, but when you crossed the boundary to the next disc, you'd get flung back outward.162.158.62.61 19:58, 15 March 2023 (UTC)
This makes about as much sense as other Flat Earth theories. 172.70.200.137 20:00, 15 March 2023 (UTC)
