# Difference between revisions of "Talk:482: Height"

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Is my understanding and maths right? --[[User:Pudder|Pudder]] ([[User talk:Pudder|talk]]) 08:08, 11 September 2014 (UTC) | Is my understanding and maths right? --[[User:Pudder|Pudder]] ([[User talk:Pudder|talk]]) 08:08, 11 September 2014 (UTC) | ||

+ | |||

+ | == Conversion of pixels to height == | ||

+ | |||

+ | height<sub>final</sub> = height<sub>initial</sub> * factor | ||

+ | |||

+ | pixels = Log<sub>base</sub>(height) | ||

+ | |||

+ | |||

+ | |||

+ | pixels<sub>final</sub> = Log<sub>base</sub>(height<sub>initial</sub> * factor) = Log<sub>base</sub>(initial) + Log<sub>base</sub>(factor) | ||

+ | |||

+ | Therefore vertical distance on this graph represents a multiplicative change in true distance from the starting point of measure. | ||

+ | |||

+ | |||

+ | pixels<sub>delta</sub> = pixels<sub>final</sub> - pixels<sub>initial</sub> = Log<sub>base</sub>(factor) | ||

+ | |||

+ | Therefore a vertical change in pixels always represents the same multiplicative factor. | ||

+ | |||

+ | |||

+ | |||

+ | base<sup>pixels<sub>delta</sub></sup> = factor | ||

+ | |||

+ | base = factor<sup>1/pixels<sub>delta</sub></sup> | ||

+ | |||

+ | From the diagram it appears that 550 pixels represents a change of x*1000000. | ||

+ | |||

+ | |||

+ | |||

+ | 1000000<sub>meters</sub><sup>1/550<sub>pixels</sub></sup> = base | ||

+ | |||

+ | 1000000<sup>1/550<sup>pixels<sub>delta</sub></sup></sup> = 1000000<sup>pixels<sub>delta</sub>/550</sup> = factor | ||

+ | |||

+ | |||

+ | The following can be used as an equation to estimate and validate the heights on the diagram, where height<sub>initial</sub> is the height of the reference point in meters, pixels<sub>delta</sub> is the vertical change in distance in pixels, and is positive if height increases and negative if height decreases. | ||

+ | |||

+ | height<sub>final</sub> = height<sub>initial</sub> * 1000000<sup>pixels<sub>delta</sub>/550</sup> | ||

+ | |||

+ | [[Special:Contributions/108.162.216.149|108.162.216.149]] 12:40, 30 September 2014 (UTC) |

## Revision as of 12:40, 30 September 2014

Are you sure it reads "missing winds"? It looks like "missing WMDs" to me, which would suggest a political reference to the US engagement of 2003 in Iraq. 109.40.138.109 02:48, 22 May 2013 (UTC)

- Yeah. Agreed. Changed. PinkAmpersand (talk) 11:23, 23 May 2013 (UTC)

"The comic starts with Black Hat throwing a cat off the edge of the universe, probably a reference to Schrodinger's cat"

- Has the editor here never heard of the "cats always land on their feet" myth? Black Hat would appear to be testing this from the extreme. Anonymous 01:43, 4 December 2013 (UTC) (and yes, that would be WMDs)
- If I am not mistaken, this is a wiki; there is no set editor. If you have a suggestion for how to improve a page, it would be apt to edit it yourself. The discussion tends to be a forum for matters that may be tangentially related to the comic, or uncertain suggestions for improving the article.
__Davidy__²²`[talk]`03:18, 4 December 2013 (UTC)

- If I am not mistaken, this is a wiki; there is no set editor. If you have a suggestion for how to improve a page, it would be apt to edit it yourself. The discussion tends to be a forum for matters that may be tangentially related to the comic, or uncertain suggestions for improving the article.
- Sorry, I wasn't aware of the proper terminology. I'll add my line shortly. Anonymous 05:13, 13 December 2013 (UTC)

- Has the editor here never heard of the "cats always land on their feet" myth? Black Hat would appear to be testing this from the extreme. Anonymous 01:43, 4 December 2013 (UTC) (and yes, that would be WMDs)

Why is there a "(?)" in "Oort Cloud"? 108.162.212.196 02:10, 15 December 2013 (UTC)

- Because it's not known if this cloud really does exist. Many objects are assumed to be there at that vast distance to the sun, but that distance is also the reason they could not be detected from earth. Voyager 1, the farthest humanmade object from Earth, will reach that region in many thousand years. --Dgbrt (talk) 21:37, 15 December 2013 (UTC)

Why is Snoop Dogg in space? 108.162.219.223 (talk) *(please sign your comments with ~~~~)*

- Because he's high as shit, man--he's so high, he's the second-furthest any person's ever been from the earth. 108.162.216.76 10:12, 6 February 2014 (UTC)

Diameter of milky way: 100 - 120 kly (Lets call it 110 kly) Suns distance to galactic centre: 27.2 kly Distance to edge of galaxy: (0.5*110)-27.2 = 27.8 kly = 263E18 Is my understanding and maths right? --Pudder (talk) 08:08, 11 September 2014 (UTC)

## Conversion of pixels to height

height_{final} = height_{initial} * factor

pixels = Log_{base}(height)

pixels_{final} = Log_{base}(height_{initial} * factor) = Log_{base}(initial) + Log_{base}(factor)

Therefore vertical distance on this graph represents a multiplicative change in true distance from the starting point of measure.

pixels_{delta} = pixels_{final} - pixels_{initial} = Log_{base}(factor)

Therefore a vertical change in pixels always represents the same multiplicative factor.

base^{pixelsdelta} = factor

base = factor^{1/pixelsdelta}

From the diagram it appears that 550 pixels represents a change of x*1000000.

1000000_{meters}^{1/550pixels} = base

1000000^{1/550pixelsdelta} = 1000000^{pixelsdelta/550} = factor

The following can be used as an equation to estimate and validate the heights on the diagram, where height_{initial} is the height of the reference point in meters, pixels_{delta} is the vertical change in distance in pixels, and is positive if height increases and negative if height decreases.

height_{final} = height_{initial} * 1000000^{pixelsdelta/550}

108.162.216.149 12:40, 30 September 2014 (UTC)