Talk:1433: Lightsaber

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I seem to remember seeing somewhere that lightsabers are actually not lasers but rather plasma held in that shape by some sort of force field. I think it should be in the explanation if it is true. Athang (talk) 06:11, 13 October 2014 (UTC)

I'd just like to know what "real laser"s have to do with lightsabers. (Other than little kids using the wrong name.) 11:55, 13 October 2014 (UTC)

Most of "scientific" explanations of lightsaber (and blaster bolts) says about plasma contained in magnetic field. For example check this SE Endless "laser sword" pun was also used in, without Luke but with massive hull breach. 06:38, 13 October 2014 (UTC)PTwr

One joking "explanation" of the light sabre conjured long ago on a newsgroup I was on had used the Fourier analysis. It proposed that the "handle" emits multiple beams of light with very well defined frequencies and amplitudes, corresponding to a Fourier series for a pulse wave with a low duty cycle - so the waveforms emitted cancel themselves after a short distance. The joke went on, saying that since the sum of the Fourier series is periodic, someone practicing the sabre on the Earth can accidentally chop off the head of someone walking on the Moon. 07:26, 13 October 2014 (UTC)

I don't think this has anything to do with the Hull Breach card game. The sentence "Hull breach all along sector five" does however sound like something from Star Trek and not like Star Wars.Condor70 (talk) 12:07, 13 October 2014 (UTC)

There is a XKCD What If discussion on infinite lasers at 12:17, 13 October 2014 (UTC)

"Because Vader slightly tilts the active lightsaber, the beam ends up slicing straight through the hull of a large section of the Death Star. " Wouldn't it would cause a breach the moment he turned it on, not waiting until he tilts it? Lomky (talk) 15:07, 13 October 2014 (UTC)

Yes, but the breach would be highly localized (the same diameter as the blade) until he tilts it. If he does so in the center of the sphere, leverage means that a slight angle change in the emitter means a huge change at the other end of the beam.Seebert (talk) 15:34, 13 October 2014 (UTC)
Darth Vader may be more machine than man, but don't you think you're overestimating his ability to hold his hand steady? You seem to be suggesting his hand wouldn't tremor enough to cause even the tiniest perturbations in the angle.Diszy (talk) 19:29, 13 October 2014 (UTC)
How far are they from the hull? The original breach would still be relatively localized (on the order of 1-2% of their distance from the hull), so if they're within a few hundred meters from the boundary it shouldn't be particularly large. (That's even assuming they're on the Death Star in the first place, as the IP below me helpfully points out; could be that the original vector simply didn't intersect the Death Star at all.)
Or of course it could be the original - it's only been several seconds or so, maybe they only noticed it that moment anyway.
A cool calculation I don't have time to do right now: assuming the blade covered a plane sector of, say, 15 degrees (I'm ignoring the twitches for a moment, though it's easy to see that they don't change the answer much), and assuming it didn't hit any nearby planets such as Endor, approximately how many planets it would've hit on its way from the galaxy? Same question for stars (though I suppose a lightsaber blade won't do much to a star). 06:51, 14 October 2014 (UTC)
They're on Endor (in the movie, at least). If the beam intersects the Death Star, it would be many hundreds of KM away. Any perturbations would be HUGE at that distance. Also, the XKCD What If book actually addresses the question of the likelihood that a beam hits anything. Diszy (talk) 12:03, 15 October 2014 (UTC)
I was basically saying that the beam didn't intersect the Death Star until being moved in panel four.
As for the book, if you're referring to What If #109, it involves a stationary (or single-burst) laser; numbers for a moving laser (that sweeps through a section of a plane) would be different. I'm also ignoring the speed of light (which is kind of important when we're talking about interstellar distances).
Estimating based on 1276: Angular Size, seems that the chance of hitting a star would be roughly (laptop size/Earth size)*(galaxy size/Proxima distance)*15/360, which comes out to one in several thousand. Which is less than I expected, actually. 15:16, 15 October 2014 (UTC)

The scene referred to in Return of the Jedi, actually takes place on the surface of Endors moon. There are trees in the background: 15:20, 13 October 2014 (UTC)

Actually, the title text says "A long time in the future, in a galaxy...", not "ago". 12:25, 13 October 2014 (UTC)

Who said otherwise? "The Star Wars opening crawl starts with the text "A long time ago..." (talk) (please sign your comments with ~~~~)

When I first read this, I took it as a game of one-up-manship. I build something, you build something better, I build something even better, you build something cooler, etc in an ever escalating spiral of coolness. So, here, Luke has built a long sabre as a way of one-upping his father, who then asks "where does [this competition] end?" Luke's response is taht the competition, like his laser sword, never ends. That also seems to fit in neatly with Randall's penchant for puns. OTOH, I could just be making up stuff inside my head :D JonS

<GASP> We now have one of the two variables needed to find the Death Star! We have direction, now all we need is distance! (talk) (please sign your comments with ~~~~)

"an unusual gamma ray burst in 2008, visible to the human eye" - I know what is meant, but perhaps a rewording? 12:56, 15 October 2014 (UTC)

Done.Iggynelix (talk) 13:43, 18 October 2014 (UTC)

"not the place for humour" uh yeah, big fate [actual citation needed] on that one -- 14:06, 20 March 2024 (UTC)