Difference between revisions of "Talk:2215: Faculty:Student Ratio"
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Times that by 10 = 71,225,071.23 for 10 microseconds of work, not bad. | Times that by 10 = 71,225,071.23 for 10 microseconds of work, not bad. | ||
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+ | You are starting with the wage too high by a factor of a million, 50 quintillions instead of 50 trillion. (I guess you're using the British terminology instead of the US amounts) Divide all you figures by a million and you get the more reasonable $71.23, which is about what others are getting. [[User:JamesCurran|JamesCurran]] ([[User talk:JamesCurran|talk]]) 16:49, 18 October 2019 (UTC) | ||
Revision as of 16:49, 18 October 2019
Hi
That student from the title text would have just barely made a cent, two if they were generous and rounded up. 172.68.65.18 00:21, 15 October 2019 (UTC)
Really? My calculations have him at about 16 cents ((5 trillion x 100) divided by (10^6 x 3600 x 24 x 365.25))
Regarding above average students not getting in, the scenario described is oversimplified. I used to work in admissions for a “highly selective” university and while applicants with perfect SATs and higher than 4.0 GPAs were routinely put on the wait list (not rejected) because we assumed that they viewed us as merely a “safety school”, if the applicant showed any interest at all in actually attending, such as having come on campus for an in person interview, campus tour, or had an alumni connection, or letter(s) of recommendation, or athletic scholarship, then of course we would make an offer, and similarly if they showed any interest as cited above after being put on the wait list then they would be top of the list to get an offer from the wait list. 162.158.63.48 03:39, 15 October 2019 (UTC)
I'm pretty sure it should be $15.85 and $69.44. Although I'm not so sure now that there's 3 other answers on this page. If someone can confirm one of these and find inaccuracies in the others, go ahead and update the page. --Seaish (talk) 07:49, 15 October 2019 (UTC)
- For a constant salary across the whole year, I got $15.85 as well. For paid working time it depends on the assumptions of working days per year and working hours per working day. I got 220 working days(250 official in my state-30 days of holiday, even though technically it is considered payed holiday....) and 39hours per week (8 per day, and 7 on friday), I get to $80.94. But, as stated that depends on the assumptions. --Lupo (talk) 09:48, 15 October 2019 (UTC)
- "Hi!" x 5'000'000'000
Hi!
I think it's a reference to "Hello, World!" test program.
It is also possible to print 5 billions of unique "Hi!" using different color (provided you have 32 bit color map for CMYK and maybe 2 differend colors of paper) 172.68.10.172 (talk) (please sign your comments with ~~~~)
- Unsigned Comment from Community Portal moved here
HI,
I disagree with the calculation for the amount of 50 trillion over 10 microseconds, its a lot more than the amount give,.
Wage = 50000000000000000000
Divide by 260 days for an average work year is a daily rate of = 192307692307692000.00
Divide that by 7.5, the average working day is an hourly rate of = 25641025641025600.00
Divide that by 60 for minutes in the hour to give a minutes rate of = 427350427350427.00
Divide that by 60 for seconds in the minute to give a seconds rate of = 7122507122507.12
Divide that by 1000 to give a millisecond rate of = 7122507122.51
Divide that by 1000 to give a microsecond rate of = 7122507.12
Times that by 10 = 71,225,071.23 for 10 microseconds of work, not bad.
You are starting with the wage too high by a factor of a million, 50 quintillions instead of 50 trillion. (I guess you're using the British terminology instead of the US amounts) Divide all you figures by a million and you get the more reasonable $71.23, which is about what others are getting. JamesCurran (talk) 16:49, 18 October 2019 (UTC)
From an ADP Payroll Specialist 162.158.234.82 (talk) (please sign your comments with ~~~~)
- 50 trillion (in english use of the word trillion) is 5E13, not 5E19 (as you used it), so instead of $71,225,071.23 it is only $71.22 for the 10 microseconds, using your assumptions on average work days and working time. --Lupo (talk) 09:35, 15 October 2019 (UTC)
- Trillion could be 1E18 in long scale, commonly referred to as Brittish, or in short scale, commonly referred to as American, it is 1E12. So the "english" use of the word trillion is ambiguous (but adding the English modifier suggests British, i.e., long scale.) I added a note to article to mention the different possible interpretations. 172.69.33.113 19:58, 15 October 2019 (UTC)
- According to your wikipedia link, nearly all English speaking countries (including the UK and therefore England) use the short scale. Therefore, in contrast to my native language (German), which uses the short scale, the long scale is the "English" meaning, even though the term (English) is not scientifically correct in this context, it helps when trying to make it clear to the many people on this wiki who natively speak a language in which the long scale is the usual one. --Lupo (talk) 06:08, 16 October 2019 (UTC)
- Trillion could be 1E18 in long scale, commonly referred to as Brittish, or in short scale, commonly referred to as American, it is 1E12. So the "english" use of the word trillion is ambiguous (but adding the English modifier suggests British, i.e., long scale.) I added a note to article to mention the different possible interpretations. 172.69.33.113 19:58, 15 October 2019 (UTC)
Is the date incorrect? The archive on xkcd says it was released on 10/14, but here it says it was released on the 15th, which would make it a tuesday comic. Landfind (talk) 14:17, 15 October 2019 (UTC)
- The date was set incorrectly by the BOT that generated this page - not sure why but likely because the time of release was just past midnight GMT. I fixed it though because it is clearly the Monday comic for 10/14. Ianrbibtitlht (talk) 15:47, 15 October 2019 (UTC)
- Here, a Monday the 14th seven or eight pm refresh did the trick. 172.68.38.64 17:37, 15 October 2019 (UTC)
um, "10e-6 / 3600 / 24 / 365 * 50e12)" does not mean what you think it means. are we geeks here or not? --162.158.158.235 08:58, 16 October 2019 (UTC)
- I changed the formula. It was not actually wrong (it worked out), but the way it was displayed does not show clearly why it is applied. Also the unit $ was missing. Feel free to further edit, if this is not correct or could be done better. --Lupo (talk) 09:22, 16 October 2019 (UTC)
Where can I enlist? 162.158.158.171 14:56, 16 October 2019 (UTC)
Effect sizes by forms of instruction
Computer-aided instruction can act as a "force multiplier" increasing the effective class size ratio depending on the type of instruction used. See tables 1 and 2 here. Too tangential or ok? 172.68.189.19 12:38, 17 October 2019 (UTC)