Difference between revisions of "Talk:849: Complex Conjugate"
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[[Special:Contributions/108.162.218.142|108.162.218.142]] 15:48, 24 June 2015 (UTC) | [[Special:Contributions/108.162.218.142|108.162.218.142]] 15:48, 24 June 2015 (UTC) | ||
| − | (a+b)*(a-b) = a^2 - b^2 . However (a+bi)*(a-bi) = a^2 + b^2 since i^2 = -1. | + | (a+b)*(a-b) = a^2 - b^2 . However (a+bi)*(a-bi) = a^2 + b^2 since i^2 = -1. {{unsigned ip|108.162.219.65}} |
Revision as of 08:29, 24 July 2015
Actually multiplying complex number (x + iy) by its complex conjugate (x - iy) does not "remove" imaginary part, but calculate square of absolute value of complex number, (x^2 + y^2). BTW. in quantum physics the wavefunction is complex valued, and its absolute value is probability density (a real valued function). --JakubNarebski (talk) 00:57, 18 December 2012 (UTC)
I got hit in the face with my complex conjugate and lost an eye. 108.162.238.114 (talk) (please sign your comments with ~~~~)
I procreated with my complex conjugate and lost myself. 108.162.216.114 19:44, 12 August 2014 (UTC)
(a+bi)*(a-bi)= a^2-b^2 not a^2+b^2 108.162.218.142 15:48, 24 June 2015 (UTC)
(a+b)*(a-b) = a^2 - b^2 . However (a+bi)*(a-bi) = a^2 + b^2 since i^2 = -1. 108.162.219.65 (talk) (please sign your comments with ~~~~)
