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Difference between revisions of "Talk:3049: Incoming Asteroid"
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:::Annoyingly, the standard phrase tends to be "the bike was in collision with a car", with the implication of perhaps equal fault, if not switched round entirely. Yes, a cyclist ''can'' be the one who "hits the blameless car", or pedestrian steps into the side of the passing cyclist (or car, bus, lorry, etc, potentially), but it's more often the other way round, and the balance of sympathies (regardless of who most erred, to result in the incident) should probably be considered by who is most damaged (trickier in foot vs bike incident, one is initially struck by a lump of metal with spinning bits and various hard protusions, the other may then be struck by(/strikes) the ground). [[Special:Contributions/172.71.241.37|172.71.241.37]] 00:09, 13 February 2025 (UTC) | :::Annoyingly, the standard phrase tends to be "the bike was in collision with a car", with the implication of perhaps equal fault, if not switched round entirely. Yes, a cyclist ''can'' be the one who "hits the blameless car", or pedestrian steps into the side of the passing cyclist (or car, bus, lorry, etc, potentially), but it's more often the other way round, and the balance of sympathies (regardless of who most erred, to result in the incident) should probably be considered by who is most damaged (trickier in foot vs bike incident, one is initially struck by a lump of metal with spinning bits and various hard protusions, the other may then be struck by(/strikes) the ground). [[Special:Contributions/172.71.241.37|172.71.241.37]] 00:09, 13 February 2025 (UTC) | ||
− | + | Seemes there is little change between a 10cm and 1m astroid. The scale skips the 100cm step. It should be : 1cm, 10, ''100'', 1m [[Special:Contributions/172.68.243.66|172.68.243.66]] 12:09, 13 February 2025 (UTC) | |
− | Seemes there is little change between a 10cm and 1m astroid. The scale skips the 100cm step. It should be : | + | :That is because 100 cm = 1 m. No step is skipped {{unsigned ip|172.70.126.169|15:22, 13 February 2025}} |
− | 1cm, 10, ''100'', 1m [[Special:Contributions/172.68.243.66|172.68.243.66]] 12:09, 13 February 2025 (UTC) | + | |
+ | Surely the other planet closest to Earth, on average, is Mercury? [[Special:Contributions/172.69.23.9|172.69.23.9]] 23:13, 13 February 2025 (UTC) | ||
+ | :Without crunching the numbers myself, it may depend upon which 'average' you mean. There's aparently fairly definite factual statements, out there, like "Venus'[s] average distance to Earth as around 25.7 million miles (41.4 million km), compared with 57 million miles (91.7 million km) for Mercury and 48.6 million miles (78.3 million km) for Mars", but also "Mercury is the nearest planet to Earth — and to every other planet in the solar system". I'm going to have to actually look at both claims, work out what's going on there (who is being wrong, or why they're right but for different reasons). [[Special:Contributions/172.71.241.145|172.71.241.145]] 02:03, 14 February 2025 (UTC) | ||
+ | :...well, seems obvious that the first one didn't mean "average (i.e. mean)", but probably "minimum". My own actual quick-and-dirty calculation (median Earth-Sun and median Planet-Sun distances, arrayed uniformly around a conjunction-to-conjunction circle for positional differences smeared free of any particular perihelion/aphelion bias, then arithmetically averaged, also without regard for any Keplerian sweeping-speeds - which should satisfactorarily smooth out the actual details ''unless'' there's a particular resonance aligning eliptic axes consistently) suggests Earth-Mercury is averaged at 1.05ish AU ('median'-based ranges from 0.55 to 1.45), Earth-Venus is 1.14ish (ranging 0.275 to 1.725), Earth-Mars 1.69ish (0.525 to 2.525), Jupiter: 5.25, Saturn: 9.62, Uranus: 19.21, Neptune: 30.21, in case I've made any stupid errors (not just approximations). | ||
+ | :But it already had occured to me that Mercury would be the "average closest planet" to ''every other planet'' (given no particularly extreme ellipses, and orbital resonances to keep them perpetually aligned). My mental exercise was to take a basic concentrjc map of orbits, use dividers to measure any given starting planet's distance from the Sun, and then sweep a circle of that radius around the planet. Where that line crosses every other inferior orbit (and any superior orbit no more than twice the size of the starting planet), it cuts those orbits into a "nearer than the Sun" arc and a "further than the Sun" arc (for r*[n>2] orbits, it's 'all' further than the Sun), with the ratio of nearer:further lengths generally being less arc vs. more arc, tending towards 1:1 only for the smallest orbits (r=lim->0). So the larger the other planet's orbit, the larger this average would be, above the chosen planet's own solar-distance, and Mercury (in the absence of anything closer to the Sun) would end up with the least additional amount above the constant distance to the Sun itself. | ||
+ | :Which I found interesting to work out, so maybe will be interesting for others, but didn't entirely trust myself until I hacked up the apparent emperical evidence, too. [[Special:Contributions/172.70.160.182|172.70.160.182]] 03:17, 14 February 2025 (UTC) |
Latest revision as of 03:17, 14 February 2025
Asteroids are surprisingly destructive even at small sizes - I remember reading somewhere that the Armageddon movie asteroid was supposed to be "the size of Arlington, Texas", but that it sounded too small so they changed it to "the size of Texas" which is a drastic size increase and also proportionally far more deadly. For scale, Arlington is 250 square km and Texas is 700 000 square km. The Chixulub asteroid that wiped out the dinosaurs was between 10 and 15 km across. If it was a perfect circle, it would have an area of between 79 and 176 sq km. Arlington would be 18 km across, still within "species" range, and Texas would be 944 km across, clearly in "new moon" territory. But it _sounds_ much cooler! Zakator (talk) 22:32, 10 February 2025 (UTC)
- And that's for asteroids with normal speed (for asteroid, which is still kinda fast). The level of danger asteroid means is proportional to kinetic energy, meaning proportional to mass and SQUARE of speed, so if it's faster, it gets to extinction level even when small ... -- Hkmaly (talk) 23:29, 10 February 2025 (UTC)
- "for asteroids with normal speed" - which is generally orbital velocity. If much faster, it would have left the solar system by now. If much slower, it has fallen into the Sun already. All objects (even Teslas) at a given distance soon have similar velocities. --PRR (talk) 00:04, 11 February 2025 (UTC)
- It could be going at a speed (similar to Earth, give or take, for the sake of being on an Earth-incident orbit) and yet have such different effects. If basically following the Earth (or leading it), it'll be relatively gentle, at least before you start considering the Earth's (and the asteroid's, in the event it's significantly large) gravity well pulling it. Well, 'gentle' in comparison to one doing the 'same speed' but in the anti-orbit, for a full head-on impact. Course, that's why we need to think of velocities, and in particular the relative ones. 172.71.241.37 01:31, 11 February 2025 (UTC)
- Considering just two-body physics... Escape speed for the Sun at the distance of Earth's orbit is 42 km/s, so that's the upper limit anything is likely to be going (otherwise it's just got one shot at us). That would be something falling towards the Sun from a very large distance. If the asteroid is moving in the opposite direction as Earth, that gets added to Earth's orbital speed of 30 km/s, for a total of 72 km/s. On the other hand, Earth has an escape speed of 11 km/s at the surface, so that's the lower bound for an impact. A 6.5x factor on speed is about a 40x factor on impact energy. Which, I'm not sure exactly how that would scale devastation, but ... I'll take the low end for anything big, thanks. 172.70.111.22 14:18, 11 February 2025 (UTC)
- "for asteroids with normal speed" - which is generally orbital velocity. If much faster, it would have left the solar system by now. If much slower, it has fallen into the Sun already. All objects (even Teslas) at a given distance soon have similar velocities. --PRR (talk) 00:04, 11 February 2025 (UTC)
The 1m danger makes me think of the meteor impact that was caught on a home security camera last July in Prince Edward Island. But the Sky & Telescope article https://skyandtelescope.org/astronomy-news/hear-the-first-ever-recording-of-a-meteorite-slamming-into-the-ground/ says that it would have been only a 6-7 cm across. Barmar (talk) 00:42, 11 February 2025 (UTC)
The sizes in the explanation are out of sync with the image. Has Randall updated it, or may it be location dependent? ~~Guest~~ 07:12, 11 February 2025 (UTC)
- I saw the comic before any explanation was put up and it was the same as it is now, all exactly powers of 10. But the labels aren't exactly at those spots, so people are probably estimating the exact point where the labels are at, though my interpretation would be that Randall meant for the labels to be attached to ranges rather than points. Tharkon (talk) 11:45, 11 February 2025 (UTC)
- Same here, all powers of 10. I don't think it makes any sense at all to guess at where on the axis the labels are meant to be when the labels themselves give an explicit number. The labels should probably be the ranges, eg "1cm to 10cm", "10cm to 1m" and so on.Mazz0 (talk) 14:00, 11 February 2025 (UTC)
"Good news everyone! We were supposed to make a delivery to the planet Tweenis 12 but it's been completely destroyed!" 162.158.94.203 11:24, 11 February 2025 (UTC)
It's not the first comic comparing our reaction to different scales of cosmic events, even though the asteroid "happiness level" does not peak like the supernova chart: https://xkcd.com/2878/ 172.69.195.172 (talk) 21:14, 11 February 2025 (please sign your comments with ~~~~)
- Indeed. This one peaks twice, if taken at face value. ;) 172.71.241.145 21:32, 11 February 2025 (UTC)
I'd noted that technically, when it comes to "asteroid collides with Earth" vs. "Earth collides with asteroid", neither is correct. In a centre-of-mass reference frame, the two objects collide. This was removed as "pedantry", but it seems appropriate to me. Thoughts? BunsenH (talk) 01:29, 12 February 2025 (UTC)
- I would say if a smaller asteroid hit Earth then yes it collides with Earth. If two similar planet sized object hit each other, then I would say they collided with each other, and if Earth hit Jupiter I would say Earth collided with Jupiter. This may not be physically correct, but it is how language and meaning works. So I would say it was correctly removed. --Kynde (talk) 11:44, 12 February 2025 (UTC)
- Yet the logic is reversed when talking about vehicles on Earth. You would say "the car collided with the bicycle" and "the train collided with the car" (or the car got hit by the train). "{Bigger object} collided with {smaller object}" in this case. --StapleFreeBatteries (talk) 23:26, 12 February 2025 (UTC)
- Annoyingly, the standard phrase tends to be "the bike was in collision with a car", with the implication of perhaps equal fault, if not switched round entirely. Yes, a cyclist can be the one who "hits the blameless car", or pedestrian steps into the side of the passing cyclist (or car, bus, lorry, etc, potentially), but it's more often the other way round, and the balance of sympathies (regardless of who most erred, to result in the incident) should probably be considered by who is most damaged (trickier in foot vs bike incident, one is initially struck by a lump of metal with spinning bits and various hard protusions, the other may then be struck by(/strikes) the ground). 172.71.241.37 00:09, 13 February 2025 (UTC)
- Yet the logic is reversed when talking about vehicles on Earth. You would say "the car collided with the bicycle" and "the train collided with the car" (or the car got hit by the train). "{Bigger object} collided with {smaller object}" in this case. --StapleFreeBatteries (talk) 23:26, 12 February 2025 (UTC)
Seemes there is little change between a 10cm and 1m astroid. The scale skips the 100cm step. It should be : 1cm, 10, 100, 1m 172.68.243.66 12:09, 13 February 2025 (UTC)
- That is because 100 cm = 1 m. No step is skipped 172.70.126.169 (talk) 15:22, 13 February 2025 (please sign your comments with ~~~~)
Surely the other planet closest to Earth, on average, is Mercury? 172.69.23.9 23:13, 13 February 2025 (UTC)
- Without crunching the numbers myself, it may depend upon which 'average' you mean. There's aparently fairly definite factual statements, out there, like "Venus'[s] average distance to Earth as around 25.7 million miles (41.4 million km), compared with 57 million miles (91.7 million km) for Mercury and 48.6 million miles (78.3 million km) for Mars", but also "Mercury is the nearest planet to Earth — and to every other planet in the solar system". I'm going to have to actually look at both claims, work out what's going on there (who is being wrong, or why they're right but for different reasons). 172.71.241.145 02:03, 14 February 2025 (UTC)
- ...well, seems obvious that the first one didn't mean "average (i.e. mean)", but probably "minimum". My own actual quick-and-dirty calculation (median Earth-Sun and median Planet-Sun distances, arrayed uniformly around a conjunction-to-conjunction circle for positional differences smeared free of any particular perihelion/aphelion bias, then arithmetically averaged, also without regard for any Keplerian sweeping-speeds - which should satisfactorarily smooth out the actual details unless there's a particular resonance aligning eliptic axes consistently) suggests Earth-Mercury is averaged at 1.05ish AU ('median'-based ranges from 0.55 to 1.45), Earth-Venus is 1.14ish (ranging 0.275 to 1.725), Earth-Mars 1.69ish (0.525 to 2.525), Jupiter: 5.25, Saturn: 9.62, Uranus: 19.21, Neptune: 30.21, in case I've made any stupid errors (not just approximations).
- But it already had occured to me that Mercury would be the "average closest planet" to every other planet (given no particularly extreme ellipses, and orbital resonances to keep them perpetually aligned). My mental exercise was to take a basic concentrjc map of orbits, use dividers to measure any given starting planet's distance from the Sun, and then sweep a circle of that radius around the planet. Where that line crosses every other inferior orbit (and any superior orbit no more than twice the size of the starting planet), it cuts those orbits into a "nearer than the Sun" arc and a "further than the Sun" arc (for r*[n>2] orbits, it's 'all' further than the Sun), with the ratio of nearer:further lengths generally being less arc vs. more arc, tending towards 1:1 only for the smallest orbits (r=lim->0). So the larger the other planet's orbit, the larger this average would be, above the chosen planet's own solar-distance, and Mercury (in the absence of anything closer to the Sun) would end up with the least additional amount above the constant distance to the Sun itself.
- Which I found interesting to work out, so maybe will be interesting for others, but didn't entirely trust myself until I hacked up the apparent emperical evidence, too. 172.70.160.182 03:17, 14 February 2025 (UTC)